I would like to use a flat spiral spring for the light-load wire winding mechanism, but our engineering team are worried that the spring will break. If the spring is properly designed, will it have a service life of 10 million times or more? Thank you.
Thank you for your question, Spring Newbie!
There are cases where various corrections are necessary when designing the flat spiral springs according to the material, shape and fixing method used. It is also necessary to consider multiple parameters for the service life calculation so that the product will not break.
When it comes to the contact type, it is important to have a lubrication method that considers friction and wear between plates and a safety design that corresponds to the torque used!
If you give us a detailed explanation of the wire winding mechanism currently under consideration, we can propose a design. If you go to contact form, it is possible to keep it private and confidential, so please feel free to contact us.
Thank you in advance!!!
When a bending moment is applied to the coil spring, the rotation angle can be calculated from the Bernoulli-Euler beam equation, and the diameter after the change can be estimated.
Similarly, if a bending moment is applied when the inner end of the flat spiral spring is fixed, can the diameter (distance from the center to the outer end) after the change be calculated?
For example, it is said it is possible to estimate the shape of the non-contact type spring with an Archimedes spiral (r=aθ) and the contact type with a parabolic spiral (r=aθ^0.5).
Can the diameter of the flat spiral spring after the rotation angle changes be expressed by the same formula? (Example: r=a’θ)
Spring Newbie, in the case of a flat spiral spring, the inner diameter shaft part and the outer diameter end part are fixed in some way to rotate, so it seems that the distance from the center to the outer diameter end part does not change in general. It may be possible to calculate the locus of the flat spiral spring portion from the inner diameter end to the outer diameter end based on the rotation operation, but it is very difficult.
